13124335404133 has 2 divisors, whose sum is σ = 13124335404134. Its totient is φ = 13124335404132.

The previous prime is 13124335404077. The next prime is 13124335404161. The reversal of 13124335404133 is 33140453342131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6670535576644 + 6453799827489 = 2582738^2 + 2540433^2 .

It is an emirp because it is prime and its reverse (33140453342131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13124335404133 - 2⁴¹ = 10925312148581 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13124335404092 and 13124335404101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124335404163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562167702066 + 6562167702067.

It is an arithmetic number, because the mean of its divisors is an integer number (6562167702067).

Almost surely, 2^{13124335404133} is an apocalyptic number.

It is an amenable number.

13124335404133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124335404133 is an equidigital number, since it uses as much as digits as its factorization.

13124335404133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 37.

Adding to 13124335404133 its reverse (33140453342131), we get a palindrome (46264788746264).

The spelling of 13124335404133 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-five million, four hundred four thousand, one hundred thirty-three".