Base | Representation |
---|---|
bin | 1011111011111100000010… |
… | …0011001101000001011010 |
3 | 1201110200020220101122201011 |
4 | 2332333000203031001122 |
5 | 3210012140004340010 |
6 | 43525125023244134 |
7 | 2523126523312306 |
oct | 276770043150132 |
9 | 51420226348634 |
10 | 13124355543130 |
11 | 420000a609937 |
12 | 157b70814964a |
13 | 74281033b430 |
14 | 3353179d2d06 |
15 | 17b5dbbe3a8a |
hex | befc08cd05a |
13124355543130 has 16 divisors (see below), whose sum is σ = 25441058437704. Its totient is φ = 4845915892800.
The previous prime is 13124355543121. The next prime is 13124355543137. The reversal of 13124355543130 is 3134555342131.
13124355543130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 11261373505209 + 1862982037921 = 3355797^2 + 1364911^2 .
It is not an unprimeable number, because it can be changed into a prime (13124355543137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50478290421 + ... + 50478290680.
Almost surely, 213124355543130 is an apocalyptic number.
13124355543130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13124355543130 is a deficient number, since it is larger than the sum of its proper divisors (12316702894574).
13124355543130 is a wasteful number, since it uses less digits than its factorization.
13124355543130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100956581121.
The product of its (nonzero) digits is 324000, while the sum is 40.
The spelling of 13124355543130 in words is "thirteen trillion, one hundred twenty-four billion, three hundred fifty-five million, five hundred forty-three thousand, one hundred thirty".
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