Base | Representation |
---|---|
bin | 1011111011111100001101… |
… | …1100101000101011001111 |
3 | 1201110200101021212021222011 |
4 | 2332333003130220223033 |
5 | 3210012234430344124 |
6 | 43525133521202051 |
7 | 2523130653430204 |
oct | 276770334505317 |
9 | 51420337767864 |
10 | 13124404153039 |
11 | 4200034aa0213 |
12 | 157b720490327 |
13 | 74281a42abaa |
14 | 335320247cab |
15 | 17b5e10e6994 |
hex | befc3728acf |
13124404153039 has 2 divisors, whose sum is σ = 13124404153040. Its totient is φ = 13124404153038.
The previous prime is 13124404152997. The next prime is 13124404153043. The reversal of 13124404153039 is 93035140442131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13124404153039 - 27 = 13124404152911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13124404152992 and 13124404153010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13124404153739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562202076519 + 6562202076520.
It is an arithmetic number, because the mean of its divisors is an integer number (6562202076520).
Almost surely, 213124404153039 is an apocalyptic number.
13124404153039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124404153039 is an equidigital number, since it uses as much as digits as its factorization.
13124404153039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 13124404153039 in words is "thirteen trillion, one hundred twenty-four billion, four hundred four million, one hundred fifty-three thousand, thirty-nine".
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