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13124413024421 is a prime number
BaseRepresentation
bin1011111011111100001111…
…1110011110100010100101
31201110200101220120000012212
42332333003332132202211
53210012244213240141
643525134435253205
72523131122016246
oct276770376364245
951420356500185
1013124413024421
114200039aaa436
12157b72344a205
1374281c215b2a
143353214b6ccd
1517b5e1c9a2eb
hexbefc3f9e8a5

13124413024421 has 2 divisors, whose sum is σ = 13124413024422. Its totient is φ = 13124413024420.

The previous prime is 13124413024403. The next prime is 13124413024441. The reversal of 13124413024421 is 12442031442131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12379490402500 + 744922621921 = 3518450^2 + 863089^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124413024421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124413024441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562206512210 + 6562206512211.

It is an arithmetic number, because the mean of its divisors is an integer number (6562206512211).

Almost surely, 213124413024421 is an apocalyptic number.

It is an amenable number.

13124413024421 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124413024421 is an equidigital number, since it uses as much as digits as its factorization.

13124413024421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 13124413024421 its reverse (12442031442131), we get a palindrome (25566444466552).

The spelling of 13124413024421 in words is "thirteen trillion, one hundred twenty-four billion, four hundred thirteen million, twenty-four thousand, four hundred twenty-one".