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13124413024517 is a prime number
BaseRepresentation
bin1011111011111100001111…
…1110011110100100000101
31201110200101220120000100102
42332333003332132210011
53210012244213241032
643525134435253445
72523131122016444
oct276770376364405
951420356500312
1013124413024517
114200039aaa513
12157b72344a285
1374281c215ba2
143353214b6d5b
1517b5e1c9a362
hexbefc3f9e905

13124413024517 has 2 divisors, whose sum is σ = 13124413024518. Its totient is φ = 13124413024516.

The previous prime is 13124413024487. The next prime is 13124413024549. The reversal of 13124413024517 is 71542031442131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13075463232001 + 48949792516 = 3616001^2 + 221246^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124413024517 - 212 = 13124413020421 is a prime.

It is a super-2 number, since 2×131244130245172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124413024577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562206512258 + 6562206512259.

It is an arithmetic number, because the mean of its divisors is an integer number (6562206512259).

Almost surely, 213124413024517 is an apocalyptic number.

It is an amenable number.

13124413024517 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124413024517 is an equidigital number, since it uses as much as digits as its factorization.

13124413024517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80640, while the sum is 38.

Adding to 13124413024517 its reverse (71542031442131), we get a palindrome (84666444466648).

The spelling of 13124413024517 in words is "thirteen trillion, one hundred twenty-four billion, four hundred thirteen million, twenty-four thousand, five hundred seventeen".