Base | Representation |
---|---|
bin | 11101110101110110101000… |
… | …010110011000011001000111 |
3 | 122012200211001210002222012202 |
4 | 131311312220112120121013 |
5 | 114200300444331300424 |
6 | 1143044420422105115 |
7 | 36434035066122242 |
oct | 3565665026303107 |
9 | 565624053088182 |
10 | 131244140103239 |
11 | 38900366619189 |
12 | 12877bb0b7b19b |
13 | 5830366889177 |
14 | 245a370a78259 |
15 | 1028e644682ae |
hex | 775da8598647 |
131244140103239 has 2 divisors, whose sum is σ = 131244140103240. Its totient is φ = 131244140103238.
The previous prime is 131244140103227. The next prime is 131244140103247. The reversal of 131244140103239 is 932301041442131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131244140103239 - 212 = 131244140099143 is a prime.
It is a super-2 number, since 2×1312441401032392 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131244140103289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65622070051619 + 65622070051620.
It is an arithmetic number, because the mean of its divisors is an integer number (65622070051620).
Almost surely, 2131244140103239 is an apocalyptic number.
131244140103239 is a deficient number, since it is larger than the sum of its proper divisors (1).
131244140103239 is an equidigital number, since it uses as much as digits as its factorization.
131244140103239 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 38.
The spelling of 131244140103239 in words is "one hundred thirty-one trillion, two hundred forty-four billion, one hundred forty million, one hundred three thousand, two hundred thirty-nine".
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