131244412001 has 2 divisors, whose sum is σ = 131244412002. Its totient is φ = 131244412000.

The previous prime is 131244411997. The next prime is 131244412003. The reversal of 131244412001 is 100214442131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125900070976 + 5344341025 = 354824^2 + 73105^2 .

It is a cyclic number.

It is not a de Polignac number, because 131244412001 - 2² = 131244411997 is a prime.

Together with 131244412003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131244412003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65622206000 + 65622206001.

It is an arithmetic number, because the mean of its divisors is an integer number (65622206001).

Almost surely, 2^131244412001 is an apocalyptic number.

It is an amenable number.

131244412001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131244412001 is an equidigital number, since it uses as much as digits as its factorization.

131244412001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 131244412001 its reverse (100214442131), we get a palindrome (231458854132).

The spelling of 131244412001 in words is "one hundred thirty-one billion, two hundred forty-four million, four hundred twelve thousand, one".