Base | Representation |
---|---|
bin | 111101000111011000… |
… | …1101100110001100011 |
3 | 110112202122111220222021 |
4 | 1322032301230301203 |
5 | 4122242032141003 |
6 | 140143131122311 |
7 | 12324234044455 |
oct | 1721661546143 |
9 | 415678456867 |
10 | 131244412003 |
11 | 5072a05a301 |
12 | 215295a3397 |
13 | c4b7948ab3 |
14 | 64d087a2d5 |
15 | 36322232bd |
hex | 1e8ec6cc63 |
131244412003 has 2 divisors, whose sum is σ = 131244412004. Its totient is φ = 131244412002.
The previous prime is 131244412001. The next prime is 131244412031. The reversal of 131244412003 is 300214442131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131244412003 - 21 = 131244412001 is a prime.
Together with 131244412001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131244412001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65622206001 + 65622206002.
It is an arithmetic number, because the mean of its divisors is an integer number (65622206002).
Almost surely, 2131244412003 is an apocalyptic number.
131244412003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131244412003 is an equidigital number, since it uses as much as digits as its factorization.
131244412003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 131244412003 its reverse (300214442131), we get a palindrome (431458854134).
The spelling of 131244412003 in words is "one hundred thirty-one billion, two hundred forty-four million, four hundred twelve thousand, three".
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