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131250150753173 is a prime number
BaseRepresentation
bin11101110101111100001110…
…100111001100001110010101
3122012201101120200012121211222
4131311330032213030032111
5114200400302043100143
61143051253055140125
736434340042605054
oct3565741647141625
9565641520177758
10131250150753173
1138902970463471
12128791a9b14645
135830ab3c1356a
14245a78105a39b
1510291b6ea6768
hex775f0e9cc395

131250150753173 has 2 divisors, whose sum is σ = 131250150753174. Its totient is φ = 131250150753172.

The previous prime is 131250150753119. The next prime is 131250150753209. The reversal of 131250150753173 is 371357051052131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85545073887364 + 45705076865809 = 9249058^2 + 6760553^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131250150753173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131250150753103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65625075376586 + 65625075376587.

It is an arithmetic number, because the mean of its divisors is an integer number (65625075376587).

Almost surely, 2131250150753173 is an apocalyptic number.

It is an amenable number.

131250150753173 is a deficient number, since it is larger than the sum of its proper divisors (1).

131250150753173 is an equidigital number, since it uses as much as digits as its factorization.

131250150753173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 330750, while the sum is 44.

The spelling of 131250150753173 in words is "one hundred thirty-one trillion, two hundred fifty billion, one hundred fifty million, seven hundred fifty-three thousand, one hundred seventy-three".