Base | Representation |
---|---|
bin | 111101001000001110… |
… | …0111110011010100111 |
3 | 110112211121102122122112 |
4 | 1322100130332122213 |
5 | 4122321232034141 |
6 | 140150013551235 |
7 | 12325025061026 |
oct | 1722034763247 |
9 | 415747378575 |
10 | 131272533671 |
11 | 50743a17554 |
12 | 21536aa551b |
13 | c4c0713b36 |
14 | 64d44ba8bd |
15 | 363492a7eb |
hex | 1e9073e6a7 |
131272533671 has 2 divisors, whose sum is σ = 131272533672. Its totient is φ = 131272533670.
The previous prime is 131272533611. The next prime is 131272533673. The reversal of 131272533671 is 176335272131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131272533671 - 230 = 130198791847 is a prime.
Together with 131272533673, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131272533673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65636266835 + 65636266836.
It is an arithmetic number, because the mean of its divisors is an integer number (65636266836).
Almost surely, 2131272533671 is an apocalyptic number.
131272533671 is a deficient number, since it is larger than the sum of its proper divisors (1).
131272533671 is an equidigital number, since it uses as much as digits as its factorization.
131272533671 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 158760, while the sum is 41.
The spelling of 131272533671 in words is "one hundred thirty-one billion, two hundred seventy-two million, five hundred thirty-three thousand, six hundred seventy-one".
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