Base | Representation |
---|---|
bin | 111101001000001110… |
… | …0111110101001101111 |
3 | 110112211121102200222101 |
4 | 1322100130332221233 |
5 | 4122321232102024 |
6 | 140150013555531 |
7 | 12325025063611 |
oct | 1722034765157 |
9 | 415747380871 |
10 | 131272534639 |
11 | 50743a18254 |
12 | 21536aa5ba7 |
13 | c4c07143cc |
14 | 64d44badb1 |
15 | 363492ac44 |
hex | 1e9073ea6f |
131272534639 has 2 divisors, whose sum is σ = 131272534640. Its totient is φ = 131272534638.
The previous prime is 131272534637. The next prime is 131272534693. The reversal of 131272534639 is 936435272131.
Together with next prime (131272534693) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131272534639 - 21 = 131272534637 is a prime.
It is a super-3 number, since 3×1312725346393 (a number of 34 digits) contains 333 as substring.
Together with 131272534637, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131272534637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65636267319 + 65636267320.
It is an arithmetic number, because the mean of its divisors is an integer number (65636267320).
Almost surely, 2131272534639 is an apocalyptic number.
131272534639 is a deficient number, since it is larger than the sum of its proper divisors (1).
131272534639 is an equidigital number, since it uses as much as digits as its factorization.
131272534639 is an evil number, because the sum of its binary digits is even.
The product of its digits is 816480, while the sum is 46.
The spelling of 131272534639 in words is "one hundred thirty-one billion, two hundred seventy-two million, five hundred thirty-four thousand, six hundred thirty-nine".
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