Base | Representation |
---|---|
bin | 1011111100001000100111… |
… | …1011011010111111100111 |
3 | 1201110222222100202202020002 |
4 | 2333002021323122333213 |
5 | 3210041044413042411 |
6 | 43530444153531515 |
7 | 2523306326551064 |
oct | 277021173327747 |
9 | 51428870682202 |
10 | 13127734112231 |
11 | 4201493737902 |
12 | 15802ab713b9b |
13 | 742c2b29c74b |
14 | 3355585c1c6b |
15 | 17b73861633b |
hex | bf089edafe7 |
13127734112231 has 2 divisors, whose sum is σ = 13127734112232. Its totient is φ = 13127734112230.
The previous prime is 13127734112197. The next prime is 13127734112239. The reversal of 13127734112231 is 13221143772131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13127734112231 - 230 = 13126660370407 is a prime.
It is a super-2 number, since 2×131277341122312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13127734112239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563867056115 + 6563867056116.
It is an arithmetic number, because the mean of its divisors is an integer number (6563867056116).
Almost surely, 213127734112231 is an apocalyptic number.
13127734112231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13127734112231 is an equidigital number, since it uses as much as digits as its factorization.
13127734112231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 42336, while the sum is 38.
Adding to 13127734112231 its reverse (13221143772131), we get a palindrome (26348877884362).
The spelling of 13127734112231 in words is "thirteen trillion, one hundred twenty-seven billion, seven hundred thirty-four million, one hundred twelve thousand, two hundred thirty-one".
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