Base | Representation |
---|---|
bin | 11101110110101010101011… |
… | …101101101110110110011010 |
3 | 122012220011022220221100202020 |
4 | 131312222223231232312122 |
5 | 114202204430432143114 |
6 | 1143130222424515310 |
7 | 36441054113042163 |
oct | 3566525355566632 |
9 | 565804286840666 |
10 | 131300031131034 |
11 | 38922037652647 |
12 | 128869aa91bb36 |
13 | 5835702c5c34c |
14 | 245cd5392c76a |
15 | 102a6360bcaa9 |
hex | 776aabb6ed9a |
131300031131034 has 16 divisors (see below), whose sum is σ = 278047124748288. Its totient is φ = 41192166629312.
The previous prime is 131300031130969. The next prime is 131300031131041. The reversal of 131300031131034 is 430131130003131.
It is a junction number, because it is equal to n+sod(n) for n = 131300031130995 and 131300031131013.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 643627603482 + ... + 643627603685.
It is an arithmetic number, because the mean of its divisors is an integer number (17377945296768).
Almost surely, 2131300031131034 is an apocalyptic number.
131300031131034 is an abundant number, since it is smaller than the sum of its proper divisors (146747093617254).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131300031131034 is a wasteful number, since it uses less digits than its factorization.
131300031131034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1287255207189.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 131300031131034 its reverse (430131130003131), we get a palindrome (561431161134165).
The spelling of 131300031131034 in words is "one hundred thirty-one trillion, three hundred billion, thirty-one million, one hundred thirty-one thousand, thirty-four".
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