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131300042311 is a prime number
BaseRepresentation
bin111101001001000010…
…1111010011001000111
3110112220112012020102001
41322102011322121013
54122400302323221
6140152435330131
712325510642114
oct1722205723107
9415815166361
10131300042311
11507584a6169
1221544150947
13c4c6325b39
1464d7ddb90b
153637061391
hex1e9217a647

131300042311 has 2 divisors, whose sum is σ = 131300042312. Its totient is φ = 131300042310.

The previous prime is 131300042309. The next prime is 131300042329. The reversal of 131300042311 is 113240003131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131300042311 - 21 = 131300042309 is a prime.

It is a super-2 number, since 2×1313000423112 (a number of 23 digits) contains 22 as substring.

Together with 131300042309, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131300042411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650021155 + 65650021156.

It is an arithmetic number, because the mean of its divisors is an integer number (65650021156).

Almost surely, 2131300042311 is an apocalyptic number.

131300042311 is a deficient number, since it is larger than the sum of its proper divisors (1).

131300042311 is an equidigital number, since it uses as much as digits as its factorization.

131300042311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 131300042311 its reverse (113240003131), we get a palindrome (244540045442).

The spelling of 131300042311 in words is "one hundred thirty-one billion, three hundred million, forty-two thousand, three hundred eleven".