Base | Representation |
---|---|
bin | 1011111100010001001011… |
… | …1001111100010111010110 |
3 | 1201111012220112000212102020 |
4 | 2333010102321330113112 |
5 | 3210110301221000342 |
6 | 43531504205554010 |
7 | 2523420303161604 |
oct | 277042271742726 |
9 | 51435815025366 |
10 | 13130032203222 |
11 | 4202462974660 |
12 | 1580831275906 |
13 | 7432064269bc |
14 | 3356d58b4874 |
15 | 17b82025c0ec |
hex | bf112e7c5d6 |
13130032203222 has 16 divisors (see below), whose sum is σ = 28647342988992. Its totient is φ = 3978797637320.
The previous prime is 13130032203209. The next prime is 13130032203311. The reversal of 13130032203222 is 22230223003131.
It is a super-3 number, since 3×131300322032223 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13130032203192 and 13130032203201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 99469940868 + ... + 99469940999.
It is an arithmetic number, because the mean of its divisors is an integer number (1790458936812).
Almost surely, 213130032203222 is an apocalyptic number.
13130032203222 is an abundant number, since it is smaller than the sum of its proper divisors (15517310785770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13130032203222 is a wasteful number, since it uses less digits than its factorization.
13130032203222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 198939881883.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 13130032203222 its reverse (22230223003131), we get a palindrome (35360255206353).
The spelling of 13130032203222 in words is "thirteen trillion, one hundred thirty billion, thirty-two million, two hundred three thousand, two hundred twenty-two".
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