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1313012121151 is a prime number
BaseRepresentation
bin10011000110110101100…
…111101111111000111111
311122112010001221200210011
4103012311213233320333
5133003022100334101
62443104530324051
7163601443611553
oct23066547577077
94575101850704
101313012121151
11466933126425
12192579129627
1396a7cb51303
144779b78b863
152424b46d751
hex131b59efe3f

1313012121151 has 2 divisors, whose sum is σ = 1313012121152. Its totient is φ = 1313012121150.

The previous prime is 1313012121143. The next prime is 1313012121173. The reversal of 1313012121151 is 1511212103131.

It is an a-pointer prime, because the next prime (1313012121173) can be obtained adding 1313012121151 to its sum of digits (22).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1313012121151 - 23 = 1313012121143 is a prime.

It is a super-3 number, since 3×13130121211513 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313012121851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656506060575 + 656506060576.

It is an arithmetic number, because the mean of its divisors is an integer number (656506060576).

Almost surely, 21313012121151 is an apocalyptic number.

1313012121151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313012121151 is an equidigital number, since it uses as much as digits as its factorization.

1313012121151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 22.

Adding to 1313012121151 its reverse (1511212103131), we get a palindrome (2824224224282).

The spelling of 1313012121151 in words is "one trillion, three hundred thirteen billion, twelve million, one hundred twenty-one thousand, one hundred fifty-one".