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131301315407 is a prime number
BaseRepresentation
bin111101001001000101…
…0110001001101001111
3110112220121120220202202
41322102022301031033
54122401114043112
6140152522512115
712325524523553
oct1722212611517
9415817526682
10131301315407
1150759195709
122154466563b
13c4c6680452
1464d824d863
1536372136c2
hex1e922b134f

131301315407 has 2 divisors, whose sum is σ = 131301315408. Its totient is φ = 131301315406.

The previous prime is 131301315293. The next prime is 131301315419. The reversal of 131301315407 is 704513103131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131301315407 - 214 = 131301299023 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131301315407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131301315487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650657703 + 65650657704.

It is an arithmetic number, because the mean of its divisors is an integer number (65650657704).

Almost surely, 2131301315407 is an apocalyptic number.

131301315407 is a deficient number, since it is larger than the sum of its proper divisors (1).

131301315407 is an equidigital number, since it uses as much as digits as its factorization.

131301315407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780, while the sum is 29.

Adding to 131301315407 its reverse (704513103131), we get a palindrome (835814418538).

The spelling of 131301315407 in words is "one hundred thirty-one billion, three hundred one million, three hundred fifteen thousand, four hundred seven".