Base | Representation |
---|---|
bin | 111101001001000101… |
… | …0110001001101001111 |
3 | 110112220121120220202202 |
4 | 1322102022301031033 |
5 | 4122401114043112 |
6 | 140152522512115 |
7 | 12325524523553 |
oct | 1722212611517 |
9 | 415817526682 |
10 | 131301315407 |
11 | 50759195709 |
12 | 2154466563b |
13 | c4c6680452 |
14 | 64d824d863 |
15 | 36372136c2 |
hex | 1e922b134f |
131301315407 has 2 divisors, whose sum is σ = 131301315408. Its totient is φ = 131301315406.
The previous prime is 131301315293. The next prime is 131301315419. The reversal of 131301315407 is 704513103131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131301315407 - 214 = 131301299023 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131301315407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131301315487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650657703 + 65650657704.
It is an arithmetic number, because the mean of its divisors is an integer number (65650657704).
Almost surely, 2131301315407 is an apocalyptic number.
131301315407 is a deficient number, since it is larger than the sum of its proper divisors (1).
131301315407 is an equidigital number, since it uses as much as digits as its factorization.
131301315407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3780, while the sum is 29.
Adding to 131301315407 its reverse (704513103131), we get a palindrome (835814418538).
The spelling of 131301315407 in words is "one hundred thirty-one billion, three hundred one million, three hundred fifteen thousand, four hundred seven".
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