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131301315419 is a prime number
BaseRepresentation
bin111101001001000101…
…0110001001101011011
3110112220121120220210012
41322102022301031123
54122401114043134
6140152522512135
712325524523601
oct1722212611533
9415817526705
10131301315419
115075919571a
122154466564b
13c4c6680461
1464d824d871
1536372136ce
hex1e922b135b

131301315419 has 2 divisors, whose sum is σ = 131301315420. Its totient is φ = 131301315418.

The previous prime is 131301315407. The next prime is 131301315421. The reversal of 131301315419 is 914513103131.

It is a strong prime.

It is an emirp because it is prime and its reverse (914513103131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131301315419 - 228 = 131032879963 is a prime.

It is a super-2 number, since 2×1313013154192 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 131301315421, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131301315449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650657709 + 65650657710.

It is an arithmetic number, because the mean of its divisors is an integer number (65650657710).

Almost surely, 2131301315419 is an apocalyptic number.

131301315419 is a deficient number, since it is larger than the sum of its proper divisors (1).

131301315419 is an equidigital number, since it uses as much as digits as its factorization.

131301315419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4860, while the sum is 32.

The spelling of 131301315419 in words is "one hundred thirty-one billion, three hundred one million, three hundred fifteen thousand, four hundred nineteen".