Base | Representation |
---|---|
bin | 1011111100010010001100… |
… | …0110111101001101100110 |
3 | 1201111020121110120010010020 |
4 | 2333010203012331031212 |
5 | 3210111330314100042 |
6 | 43531551200340010 |
7 | 2523430113634065 |
oct | 277044306751546 |
9 | 51436543503106 |
10 | 13130304050022 |
11 | 420259236a135 |
12 | 15808a8314606 |
13 | 74324a8482b3 |
14 | 33571da3a1dc |
15 | 17b8390593ec |
hex | bf1231bd366 |
13130304050022 has 32 divisors (see below), whose sum is σ = 27162933894144. Its totient is φ = 4226955482400.
The previous prime is 13130304050011. The next prime is 13130304050023. The reversal of 13130304050022 is 22005040303131.
It is a junction number, because it is equal to n+sod(n) for n = 13130304049974 and 13130304050001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13130304050023) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71795673 + ... + 71978324.
It is an arithmetic number, because the mean of its divisors is an integer number (848841684192).
Almost surely, 213130304050022 is an apocalyptic number.
13130304050022 is an abundant number, since it is smaller than the sum of its proper divisors (14032629844122).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13130304050022 is a wasteful number, since it uses less digits than its factorization.
13130304050022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143774524.
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 13130304050022 its reverse (22005040303131), we get a palindrome (35135344353153).
The spelling of 13130304050022 in words is "thirteen trillion, one hundred thirty billion, three hundred four million, fifty thousand, twenty-two".
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