Base | Representation |
---|---|
bin | 11101110110101101100011… |
… | …111100100010011101111111 |
3 | 122012220110022022222210121121 |
4 | 131312231203330202131333 |
5 | 114202232243214121343 |
6 | 1143131453241211411 |
7 | 36441223524133006 |
oct | 3566554374423577 |
9 | 565813268883547 |
10 | 131303122020223 |
11 | 3892338335141a |
12 | 12887511a90b67 |
13 | 5835aa641746a |
14 | 245d168233c3d |
15 | 102a767616aed |
hex | 776b63f2277f |
131303122020223 has 2 divisors, whose sum is σ = 131303122020224. Its totient is φ = 131303122020222.
The previous prime is 131303122020193. The next prime is 131303122020271. The reversal of 131303122020223 is 322020221303131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131303122020223 - 221 = 131303119923071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131303122020523) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651561010111 + 65651561010112.
It is an arithmetic number, because the mean of its divisors is an integer number (65651561010112).
Almost surely, 2131303122020223 is an apocalyptic number.
131303122020223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303122020223 is an equidigital number, since it uses as much as digits as its factorization.
131303122020223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131303122020223 its reverse (322020221303131), we get a palindrome (453323343323354).
The spelling of 131303122020223 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred twenty-two million, twenty thousand, two hundred twenty-three".
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