Base | Representation |
---|---|
bin | 10011000110110111010… |
… | …111100001010001101111 |
3 | 11122112012010002022012102 |
4 | 103012313113201101233 |
5 | 133003102100441143 |
6 | 2443111454325315 |
7 | 163602250634234 |
oct | 23066727412157 |
9 | 4575163068172 |
10 | 1313041421423 |
11 | 466948719126 |
12 | 192586ab983b |
13 | 96a85c3c954 |
14 | 477a161778b |
15 | 2424dd0a0b8 |
hex | 131b75e146f |
1313041421423 has 2 divisors, whose sum is σ = 1313041421424. Its totient is φ = 1313041421422.
The previous prime is 1313041421401. The next prime is 1313041421449. The reversal of 1313041421423 is 3241241403131.
It is a weak prime.
It is an emirp because it is prime and its reverse (3241241403131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313041421423 - 26 = 1313041421359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313041421023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656520710711 + 656520710712.
It is an arithmetic number, because the mean of its divisors is an integer number (656520710712).
Almost surely, 21313041421423 is an apocalyptic number.
1313041421423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313041421423 is an equidigital number, since it uses as much as digits as its factorization.
1313041421423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1313041421423 its reverse (3241241403131), we get a palindrome (4554282824554).
The spelling of 1313041421423 in words is "one trillion, three hundred thirteen billion, forty-one million, four hundred twenty-one thousand, four hundred twenty-three".
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