Base | Representation |
---|---|
bin | 10011000110110111010… |
… | …111100001010001011001 |
3 | 11122112012010002022011121 |
4 | 103012313113201101121 |
5 | 133003102100441101 |
6 | 2443111454325241 |
7 | 163602250634203 |
oct | 23066727412131 |
9 | 4575163068147 |
10 | 1313041421401 |
11 | 466948719106 |
12 | 192586ab9821 |
13 | 96a85c3c938 |
14 | 477a1617773 |
15 | 2424dd0a0a1 |
hex | 131b75e1459 |
1313041421401 has 2 divisors, whose sum is σ = 1313041421402. Its totient is φ = 1313041421400.
The previous prime is 1313041421399. The next prime is 1313041421423. The reversal of 1313041421401 is 1041241403131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1257760007001 + 55281414400 = 1121499^2 + 235120^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313041421401 - 21 = 1313041421399 is a prime.
Together with 1313041421399, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1313041421491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656520710700 + 656520710701.
It is an arithmetic number, because the mean of its divisors is an integer number (656520710701).
Almost surely, 21313041421401 is an apocalyptic number.
It is an amenable number.
1313041421401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313041421401 is an equidigital number, since it uses as much as digits as its factorization.
1313041421401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1313041421401 its reverse (1041241403131), we get a palindrome (2354282824532).
The spelling of 1313041421401 in words is "one trillion, three hundred thirteen billion, forty-one million, four hundred twenty-one thousand, four hundred one".
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