Base | Representation |
---|---|
bin | 1011111100010010101011… |
… | …0110110101100110111111 |
3 | 1201111020221112011102000011 |
4 | 2333010222312311212333 |
5 | 3210112112103323203 |
6 | 43532012122444051 |
7 | 2523433252563244 |
oct | 277045266654677 |
9 | 51436845142004 |
10 | 13130434042303 |
11 | 4202649786276 |
12 | 1580923963627 |
13 | 74326b7603c6 |
14 | 335732dd75cb |
15 | 17b84568576d |
hex | bf12adb59bf |
13130434042303 has 2 divisors, whose sum is σ = 13130434042304. Its totient is φ = 13130434042302.
The previous prime is 13130434042273. The next prime is 13130434042333. The reversal of 13130434042303 is 30324043403131.
It is a balanced prime because it is at equal distance from previous prime (13130434042273) and next prime (13130434042333).
It is a cyclic number.
It is not a de Polignac number, because 13130434042303 - 225 = 13130400487871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13130434042333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565217021151 + 6565217021152.
It is an arithmetic number, because the mean of its divisors is an integer number (6565217021152).
Almost surely, 213130434042303 is an apocalyptic number.
13130434042303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130434042303 is an equidigital number, since it uses as much as digits as its factorization.
13130434042303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 13130434042303 its reverse (30324043403131), we get a palindrome (43454477445434).
The spelling of 13130434042303 in words is "thirteen trillion, one hundred thirty billion, four hundred thirty-four million, forty-two thousand, three hundred three".
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