Base | Representation |
---|---|
bin | 1011111100010010101011… |
… | …0111111110100110000010 |
3 | 1201111020221112201121002021 |
4 | 2333010222313332212002 |
5 | 3210112112142410000 |
6 | 43532012133112054 |
7 | 2523433255246642 |
oct | 277045267764602 |
9 | 51436845647067 |
10 | 13130434341250 |
11 | 420264996a936 |
12 | 1580923a8862a |
13 | 74326b8364b5 |
14 | 335733074522 |
15 | 17b8456e411a |
hex | bf12adfe982 |
13130434341250 has 20 divisors (see below), whose sum is σ = 24611686131582. Its totient is φ = 5252173736000.
The previous prime is 13130434341151. The next prime is 13130434341281. The reversal of 13130434341250 is 5214343403131.
It can be written as a sum of positive squares in 5 ways, for example, as 240991646281 + 12889442694969 = 490909^2 + 3590187^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 5252172487 + ... + 5252174986.
Almost surely, 213130434341250 is an apocalyptic number.
13130434341250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13130434341250 is a deficient number, since it is larger than the sum of its proper divisors (11481251790332).
13130434341250 is an equidigital number, since it uses as much as digits as its factorization.
13130434341250 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10504347495 (or 10504347480 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 13130434341250 its reverse (5214343403131), we get a palindrome (18344777744381).
The spelling of 13130434341250 in words is "thirteen trillion, one hundred thirty billion, four hundred thirty-four million, three hundred forty-one thousand, two hundred fifty".
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