Base | Representation |
---|---|
bin | 10011000110111000000… |
… | …001100100101001110101 |
3 | 11122112012212211101010012 |
4 | 103012320001210221311 |
5 | 133003112411222201 |
6 | 2443112530510005 |
7 | 163602443426642 |
oct | 23067001445165 |
9 | 4575185741105 |
10 | 1313052445301 |
11 | 466953968573 |
12 | 19258a735305 |
13 | 96a882cc55c |
14 | 477a2c86dc9 |
15 | 2424ec865bb |
hex | 131b8064a75 |
1313052445301 has 2 divisors, whose sum is σ = 1313052445302. Its totient is φ = 1313052445300.
The previous prime is 1313052445241. The next prime is 1313052445321. The reversal of 1313052445301 is 1035442503131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 742311480625 + 570740964676 = 861575^2 + 755474^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313052445301 is a prime.
It is a super-2 number, since 2×13130524453012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313052445321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656526222650 + 656526222651.
It is an arithmetic number, because the mean of its divisors is an integer number (656526222651).
Almost surely, 21313052445301 is an apocalyptic number.
It is an amenable number.
1313052445301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313052445301 is an equidigital number, since it uses as much as digits as its factorization.
1313052445301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 1313052445301 its reverse (1035442503131), we get a palindrome (2348494948432).
The spelling of 1313052445301 in words is "one trillion, three hundred thirteen billion, fifty-two million, four hundred forty-five thousand, three hundred one".
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