1313100201431 has 2 divisors, whose sum is σ = 1313100201432. Its totient is φ = 1313100201430.

The previous prime is 1313100201407. The next prime is 1313100201433. The reversal of 1313100201431 is 1341020013131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1313100201431 - 2⁶ = 1313100201367 is a prime.

It is a super-2 number, since 2×1313100201431² (a number of 25 digits) contains 22 as substring.

Together with 1313100201433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313100201433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656550100715 + 656550100716.

It is an arithmetic number, because the mean of its divisors is an integer number (656550100716).

Almost surely, 2^{1313100201431} is an apocalyptic number.

1313100201431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313100201431 is an equidigital number, since it uses as much as digits as its factorization.

1313100201431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1313100201431 its reverse (1341020013131), we get a palindrome (2654120214562).

The spelling of 1313100201431 in words is "one trillion, three hundred thirteen billion, one hundred million, two hundred one thousand, four hundred thirty-one".