13131021719 has 2 divisors, whose sum is σ = 13131021720. Its totient is φ = 13131021718.

The previous prime is 13131021713. The next prime is 13131021721. The reversal of 13131021719 is 91712013131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13131021719 is a prime.

It is a super-2 number, since 2×13131021719² (a number of 21 digits) contains 22 as substring.

Together with 13131021721, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13131021691 and 13131021700.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131021713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565510859 + 6565510860.

It is an arithmetic number, because the mean of its divisors is an integer number (6565510860).

Almost surely, 2^13131021719 is an apocalyptic number.

13131021719 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131021719 is an equidigital number, since it uses as much as digits as its factorization.

13131021719 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134, while the sum is 29.

The spelling of 13131021719 in words is "thirteen billion, one hundred thirty-one million, twenty-one thousand, seven hundred nineteen".