Base | Representation |
---|---|
bin | 1011111100010100111011… |
… | …1110111000100110110111 |
3 | 1201111022111202121221002121 |
4 | 2333011032332320212313 |
5 | 3210114332233202021 |
6 | 43532152213220411 |
7 | 2523454262343211 |
oct | 277051676704667 |
9 | 51438452557077 |
10 | 13131040131511 |
11 | 420292a913045 |
12 | 1580a72931707 |
13 | 7433371ab783 |
14 | 33578d6c75b1 |
15 | 17b87d9a7741 |
hex | bf14efb89b7 |
13131040131511 has 32 divisors (see below), whose sum is σ = 14221215360000. Its totient is φ = 12078699950592.
The previous prime is 13131040131467. The next prime is 13131040131527. The reversal of 13131040131511 is 11513104013131.
It is a cyclic number.
It is not a de Polignac number, because 13131040131511 - 231 = 13128892647863 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13131040131571) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 263243505 + ... + 263293381.
It is an arithmetic number, because the mean of its divisors is an integer number (444412980000).
Almost surely, 213131040131511 is an apocalyptic number.
13131040131511 is a deficient number, since it is larger than the sum of its proper divisors (1090175228489).
13131040131511 is a wasteful number, since it uses less digits than its factorization.
13131040131511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51471.
The product of its (nonzero) digits is 540, while the sum is 25.
Adding to 13131040131511 its reverse (11513104013131), we get a palindrome (24644144144642).
The spelling of 13131040131511 in words is "thirteen trillion, one hundred thirty-one billion, forty million, one hundred thirty-one thousand, five hundred eleven".
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