131311100121163 has 2 divisors, whose sum is σ = 131311100121164. Its totient is φ = 131311100121162.

The previous prime is 131311100121161. The next prime is 131311100121209. The reversal of 131311100121163 is 361121001113131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131311100121163 - 2¹ = 131311100121161 is a prime.

It is a super-3 number, since 3×131311100121163³ (a number of 43 digits) contains 333 as substring.

Together with 131311100121161, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (131311100121161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655550060581 + 65655550060582.

It is an arithmetic number, because the mean of its divisors is an integer number (65655550060582).

Almost surely, 2^{131311100121163} is an apocalyptic number.

131311100121163 is a deficient number, since it is larger than the sum of its proper divisors (1).

131311100121163 is an equidigital number, since it uses as much as digits as its factorization.

131311100121163 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 25.

Adding to 131311100121163 its reverse (361121001113131), we get a palindrome (492432101234294).

The spelling of 131311100121163 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred million, one hundred twenty-one thousand, one hundred sixty-three".