Base | Representation |
---|---|
bin | 11101110110110100111111… |
… | …100011001001100101001011 |
3 | 122012221012220102110012110102 |
4 | 131312310333203021211023 |
5 | 114202400113414210444 |
6 | 1143135253121240015 |
7 | 36441625334065133 |
oct | 3566647743114513 |
9 | 565835812405412 |
10 | 131311101319499 |
11 | 389267a8470032 |
12 | 12888b7a19300b |
13 | 583677859021a |
14 | 245d6c3c6dac3 |
15 | 102aa82dc384e |
hex | 776d3f8c994b |
131311101319499 has 2 divisors, whose sum is σ = 131311101319500. Its totient is φ = 131311101319498.
The previous prime is 131311101319471. The next prime is 131311101319513. The reversal of 131311101319499 is 994913101113131.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (994913101113131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131311101319499 is a prime.
It is a super-2 number, since 2×1313111013194992 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131311101319429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655550659749 + 65655550659750.
It is an arithmetic number, because the mean of its divisors is an integer number (65655550659750).
Almost surely, 2131311101319499 is an apocalyptic number.
131311101319499 is a deficient number, since it is larger than the sum of its proper divisors (1).
131311101319499 is an equidigital number, since it uses as much as digits as its factorization.
131311101319499 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78732, while the sum is 47.
The spelling of 131311101319499 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred one million, three hundred nineteen thousand, four hundred ninety-nine".
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