Base | Representation |
---|---|
bin | 11101110110110101000001… |
… | …010001010111011110010111 |
3 | 122012221012222102211002212012 |
4 | 131312311001101113132113 |
5 | 114202400143313242442 |
6 | 1143135300032414435 |
7 | 36441626134502426 |
oct | 3566650121273627 |
9 | 565835872732765 |
10 | 131311130212247 |
11 | 38926812804637 |
12 | 12888b879a741b |
13 | 583678156821b |
14 | 245d6c7a312bd |
15 | 102aa856ce582 |
hex | 776d41457797 |
131311130212247 has 2 divisors, whose sum is σ = 131311130212248. Its totient is φ = 131311130212246.
The previous prime is 131311130212217. The next prime is 131311130212253. The reversal of 131311130212247 is 742212031113131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131311130212247 - 28 = 131311130211991 is a prime.
It is a super-2 number, since 2×1313111302122472 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131311130212217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655565106123 + 65655565106124.
It is an arithmetic number, because the mean of its divisors is an integer number (65655565106124).
Almost surely, 2131311130212247 is an apocalyptic number.
131311130212247 is a deficient number, since it is larger than the sum of its proper divisors (1).
131311130212247 is an equidigital number, since it uses as much as digits as its factorization.
131311130212247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 32.
Adding to 131311130212247 its reverse (742212031113131), we get a palindrome (873523161325378).
The spelling of 131311130212247 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred thirty million, two hundred twelve thousand, two hundred forty-seven".
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