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131311130212247 is a prime number
BaseRepresentation
bin11101110110110101000001…
…010001010111011110010111
3122012221012222102211002212012
4131312311001101113132113
5114202400143313242442
61143135300032414435
736441626134502426
oct3566650121273627
9565835872732765
10131311130212247
1138926812804637
1212888b879a741b
13583678156821b
14245d6c7a312bd
15102aa856ce582
hex776d41457797

131311130212247 has 2 divisors, whose sum is σ = 131311130212248. Its totient is φ = 131311130212246.

The previous prime is 131311130212217. The next prime is 131311130212253. The reversal of 131311130212247 is 742212031113131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131311130212247 - 28 = 131311130211991 is a prime.

It is a super-2 number, since 2×1313111302122472 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131311130212217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655565106123 + 65655565106124.

It is an arithmetic number, because the mean of its divisors is an integer number (65655565106124).

Almost surely, 2131311130212247 is an apocalyptic number.

131311130212247 is a deficient number, since it is larger than the sum of its proper divisors (1).

131311130212247 is an equidigital number, since it uses as much as digits as its factorization.

131311130212247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 32.

Adding to 131311130212247 its reverse (742212031113131), we get a palindrome (873523161325378).

The spelling of 131311130212247 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred thirty million, two hundred twelve thousand, two hundred forty-seven".