1313112109 has 2 divisors, whose sum is σ = 1313112110. Its totient is φ = 1313112108.

The previous prime is 1313112091. The next prime is 1313112131. The reversal of 1313112109 is 9012113131.

Together with previous prime (1313112091) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (1313112131) can be obtained adding 1313112109 to its sum of digits (22).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1281998025 + 31114084 = 35805^2 + 5578^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313112109 - 2⁵ = 1313112077 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1313112109.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313112709) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656556054 + 656556055.

It is an arithmetic number, because the mean of its divisors is an integer number (656556055).

Almost surely, 2^1313112109 is an apocalyptic number.

It is an amenable number.

1313112109 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313112109 is an equidigital number, since it uses as much as digits as its factorization.

1313112109 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 22.

The square root of 1313112109 is about 36236.8887875325. Note that the first 3 decimals coincide. The cubic root of 1313112109 is about 1095.0499644292.

The spelling of 1313112109 in words is "one billion, three hundred thirteen million, one hundred twelve thousand, one hundred nine".