Base | Representation |
---|---|
bin | 1011111100010101100010… |
… | …0110000111100010001110 |
3 | 1201111022221000002210020221 |
4 | 2333011120212013202032 |
5 | 3210120200030124324 |
6 | 43532220214101554 |
7 | 2523461261242345 |
oct | 277053046074216 |
9 | 51438830083227 |
10 | 13131201411214 |
11 | 4202a02959957 |
12 | 1580ab894a8ba |
13 | 743361729853 |
14 | 3357a6caab5c |
15 | 17b88cc140e4 |
hex | bf15898788e |
13131201411214 has 4 divisors (see below), whose sum is σ = 19696802116824. Its totient is φ = 6565600705606.
The previous prime is 13131201411187. The next prime is 13131201411359. The reversal of 13131201411214 is 41211410213131.
13131201411214 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282800352802 + ... + 3282800352805.
It is an arithmetic number, because the mean of its divisors is an integer number (4924200529206).
Almost surely, 213131201411214 is an apocalyptic number.
13131201411214 is a deficient number, since it is larger than the sum of its proper divisors (6565600705610).
13131201411214 is an equidigital number, since it uses as much as digits as its factorization.
13131201411214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6565600705609.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 13131201411214 its reverse (41211410213131), we get a palindrome (54342611624345).
The spelling of 13131201411214 in words is "thirteen trillion, one hundred thirty-one billion, two hundred one million, four hundred eleven thousand, two hundred fourteen".
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