Base | Representation |
---|---|
bin | 1011111100010101100010… |
… | …0110000111100101011110 |
3 | 1201111022221000002210112122 |
4 | 2333011120212013211132 |
5 | 3210120200030131142 |
6 | 43532220214102542 |
7 | 2523461261243063 |
oct | 277053046074536 |
9 | 51438830083478 |
10 | 13131201411422 |
11 | 4202a0295a026 |
12 | 1580ab894aa52 |
13 | 743361729983 |
14 | 3357a6caac6a |
15 | 17b88cc141d2 |
hex | bf15898795e |
13131201411422 has 4 divisors (see below), whose sum is σ = 19696802117136. Its totient is φ = 6565600705710.
The previous prime is 13131201411409. The next prime is 13131201411457. The reversal of 13131201411422 is 22411410213131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×131312014114222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13131201411391 and 13131201411400.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282800352854 + ... + 3282800352857.
It is an arithmetic number, because the mean of its divisors is an integer number (4924200529284).
Almost surely, 213131201411422 is an apocalyptic number.
13131201411422 is a deficient number, since it is larger than the sum of its proper divisors (6565600705714).
13131201411422 is an equidigital number, since it uses as much as digits as its factorization.
13131201411422 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6565600705713.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 13131201411422 its reverse (22411410213131), we get a palindrome (35542611624553).
The spelling of 13131201411422 in words is "thirteen trillion, one hundred thirty-one billion, two hundred one million, four hundred eleven thousand, four hundred twenty-two".
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