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13131201411422 = 26565600705711
BaseRepresentation
bin1011111100010101100010…
…0110000111100101011110
31201111022221000002210112122
42333011120212013211132
53210120200030131142
643532220214102542
72523461261243063
oct277053046074536
951438830083478
1013131201411422
114202a0295a026
121580ab894aa52
13743361729983
143357a6caac6a
1517b88cc141d2
hexbf15898795e

13131201411422 has 4 divisors (see below), whose sum is σ = 19696802117136. Its totient is φ = 6565600705710.

The previous prime is 13131201411409. The next prime is 13131201411457. The reversal of 13131201411422 is 22411410213131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×131312014114222 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13131201411391 and 13131201411400.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282800352854 + ... + 3282800352857.

It is an arithmetic number, because the mean of its divisors is an integer number (4924200529284).

Almost surely, 213131201411422 is an apocalyptic number.

13131201411422 is a deficient number, since it is larger than the sum of its proper divisors (6565600705714).

13131201411422 is an equidigital number, since it uses as much as digits as its factorization.

13131201411422 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6565600705713.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 13131201411422 its reverse (22411410213131), we get a palindrome (35542611624553).

The spelling of 13131201411422 in words is "thirteen trillion, one hundred thirty-one billion, two hundred one million, four hundred eleven thousand, four hundred twenty-two".

Divisors: 1 2 6565600705711 13131201411422