Base | Representation |
---|---|
bin | 1011111100010101100010… |
… | …1010000011011011111001 |
3 | 1201111022221002001012121021 |
4 | 2333011120222003123321 |
5 | 3210120200311134001 |
6 | 43532220252142441 |
7 | 2523461303100436 |
oct | 277053052033371 |
9 | 51438832035537 |
10 | 13131202443001 |
11 | 4202a034a4075 |
12 | 1580ab9167a21 |
13 | 7433619cb386 |
14 | 3357a7098b8d |
15 | 17b88cd69ba1 |
hex | bf158a836f9 |
13131202443001 has 2 divisors, whose sum is σ = 13131202443002. Its totient is φ = 13131202443000.
The previous prime is 13131202442999. The next prime is 13131202443017. The reversal of 13131202443001 is 10034420213131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9160767608976 + 3970434834025 = 3026676^2 + 1992595^2 .
It is a cyclic number.
It is not a de Polignac number, because 13131202443001 - 21 = 13131202442999 is a prime.
Together with 13131202442999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13131202443701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565601221500 + 6565601221501.
It is an arithmetic number, because the mean of its divisors is an integer number (6565601221501).
Almost surely, 213131202443001 is an apocalyptic number.
It is an amenable number.
13131202443001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131202443001 is an equidigital number, since it uses as much as digits as its factorization.
13131202443001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13131202443001 its reverse (10034420213131), we get a palindrome (23165622656132).
The spelling of 13131202443001 in words is "thirteen trillion, one hundred thirty-one billion, two hundred two million, four hundred forty-three thousand, one".
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