Base | Representation |
---|---|
bin | 111101001001011001… |
… | …1111010111010111100 |
3 | 110112221100212222200221 |
4 | 1322102303322322330 |
5 | 4122411344244400 |
6 | 140153550031124 |
7 | 12326015313553 |
oct | 1722263727274 |
9 | 415840788627 |
10 | 131312103100 |
11 | 50764293662 |
12 | 215481a84a4 |
13 | c4c89896b9 |
14 | 64d985ad9a |
15 | 3638144c1a |
hex | 1e92cfaebc |
131312103100 has 18 divisors (see below), whose sum is σ = 284947263944. Its totient is φ = 52524841200.
The previous prime is 131312103059. The next prime is 131312103101. The reversal of 131312103100 is 1301213131.
It is a super-2 number, since 2×1313121031002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131312103101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 656560416 + ... + 656560615.
Almost surely, 2131312103100 is an apocalyptic number.
131312103100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131312103100 is an abundant number, since it is smaller than the sum of its proper divisors (153635160844).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131312103100 is a wasteful number, since it uses less digits than its factorization.
131312103100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1313121045 (or 1313121038 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131312103100 its reverse (1301213131), we get a palindrome (132613316231).
The spelling of 131312103100 in words is "one hundred thirty-one billion, three hundred twelve million, one hundred three thousand, one hundred".
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