Base | Representation |
---|---|
bin | 1011111100010101100100… |
… | …1111011100010001100111 |
3 | 1201111022221202111011010212 |
4 | 2333011121033130101213 |
5 | 3210120210313302241 |
6 | 43532221242210035 |
7 | 2523461452311125 |
oct | 277053117342147 |
9 | 51438852434125 |
10 | 13131212244071 |
11 | 4202a08a88829 |
12 | 1580b004b391b |
13 | 743363a5051c |
14 | 3357a84ca915 |
15 | 17b88db53beb |
hex | bf1593dc467 |
13131212244071 has 2 divisors, whose sum is σ = 13131212244072. Its totient is φ = 13131212244070.
The previous prime is 13131212244041. The next prime is 13131212244121. The reversal of 13131212244071 is 17044221213131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13131212244071 - 222 = 13131208049767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131212244011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565606122035 + 6565606122036.
It is an arithmetic number, because the mean of its divisors is an integer number (6565606122036).
Almost surely, 213131212244071 is an apocalyptic number.
13131212244071 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131212244071 is an equidigital number, since it uses as much as digits as its factorization.
13131212244071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 32.
The spelling of 13131212244071 in words is "thirteen trillion, one hundred thirty-one billion, two hundred twelve million, two hundred forty-four thousand, seventy-one".
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