Base | Representation |
---|---|
bin | 11101110110110110111111… |
… | …001101100001100110111111 |
3 | 122012221102102200122200011012 |
4 | 131312312333031201212333 |
5 | 114202414010220300044 |
6 | 1143140245431545435 |
7 | 36442032402156344 |
oct | 3566667715414677 |
9 | 565842380580135 |
10 | 131313243134399 |
11 | 389276a7469297 |
12 | 1288947752b27b |
13 | 5836a2a22ba11 |
14 | 245d8484c27cb |
15 | 102ab5ae4a59e |
hex | 776dbf3619bf |
131313243134399 has 2 divisors, whose sum is σ = 131313243134400. Its totient is φ = 131313243134398.
The previous prime is 131313243134291. The next prime is 131313243134449. The reversal of 131313243134399 is 993431342313131.
It is an a-pointer prime, because the next prime (131313243134449) can be obtained adding 131313243134399 to its sum of digits (50).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131313243134399 is a prime.
It is a super-2 number, since 2×1313132431343992 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131313243134699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656621567199 + 65656621567200.
It is an arithmetic number, because the mean of its divisors is an integer number (65656621567200).
Almost surely, 2131313243134399 is an apocalyptic number.
131313243134399 is a deficient number, since it is larger than the sum of its proper divisors (1).
131313243134399 is an equidigital number, since it uses as much as digits as its factorization.
131313243134399 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1889568, while the sum is 50.
The spelling of 131313243134399 in words is "one hundred thirty-one trillion, three hundred thirteen billion, two hundred forty-three million, one hundred thirty-four thousand, three hundred ninety-nine".
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