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1313143545253 is a prime number
BaseRepresentation
bin10011000110111101011…
…101000101110110100101
311122112110020020201202111
4103012331131011312211
5133003304221422003
62443125543241021
7163604630653321
oct23067535056645
94575406221674
101313143545253
114669a0330291
121925b5149171
1396aa1148057
14477b0ddc981
1524257c7de6d
hex131bd745da5

1313143545253 has 2 divisors, whose sum is σ = 1313143545254. Its totient is φ = 1313143545252.

The previous prime is 1313143545151. The next prime is 1313143545319. The reversal of 1313143545253 is 3525453413131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1313137230084 + 6315169 = 1145922^2 + 2513^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313143545253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313143545653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656571772626 + 656571772627.

It is an arithmetic number, because the mean of its divisors is an integer number (656571772627).

Almost surely, 21313143545253 is an apocalyptic number.

It is an amenable number.

1313143545253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313143545253 is an equidigital number, since it uses as much as digits as its factorization.

1313143545253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 324000, while the sum is 40.

Adding to 1313143545253 its reverse (3525453413131), we get a palindrome (4838596958384).

The spelling of 1313143545253 in words is "one trillion, three hundred thirteen billion, one hundred forty-three million, five hundred forty-five thousand, two hundred fifty-three".