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1313143545151 is a prime number
BaseRepresentation
bin10011000110111101011…
…101000101110100111111
311122112110020020201121201
4103012331131011310333
5133003304221421101
62443125543240331
7163604630653114
oct23067535056477
94575406221551
101313143545151
114669a03301a9
121925b51490a7
1396aa1147ca9
14477b0ddc90b
1524257c7de01
hex131bd745d3f

1313143545151 has 2 divisors, whose sum is σ = 1313143545152. Its totient is φ = 1313143545150.

The previous prime is 1313143545113. The next prime is 1313143545253. The reversal of 1313143545151 is 1515453413131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1313143545151 - 225 = 1313109990719 is a prime.

It is a super-2 number, since 2×13131435451512 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1313143545151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313143545751) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656571772575 + 656571772576.

It is an arithmetic number, because the mean of its divisors is an integer number (656571772576).

Almost surely, 21313143545151 is an apocalyptic number.

1313143545151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313143545151 is an equidigital number, since it uses as much as digits as its factorization.

1313143545151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54000, while the sum is 37.

Adding to 1313143545151 its reverse (1515453413131), we get a palindrome (2828596958282).

The spelling of 1313143545151 in words is "one trillion, three hundred thirteen billion, one hundred forty-three million, five hundred forty-five thousand, one hundred fifty-one".