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1313151143903 is a prime number
BaseRepresentation
bin10011000110111101111…
…010000100111111011111
311122112110202112210010222
4103012331322010333133
5133003313143101103
62443130414151555
7163605052361654
oct23067572047737
94575422483128
101313151143903
114669a4650265
121925b77b25bb
1396aa28a88b1
14477b2019c2b
1524258780638
hex131bde84fdf

1313151143903 has 2 divisors, whose sum is σ = 1313151143904. Its totient is φ = 1313151143902.

The previous prime is 1313151143893. The next prime is 1313151143917. The reversal of 1313151143903 is 3093411513131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1313151143903 - 210 = 1313151142879 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313151143503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656575571951 + 656575571952.

It is an arithmetic number, because the mean of its divisors is an integer number (656575571952).

Almost surely, 21313151143903 is an apocalyptic number.

1313151143903 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313151143903 is an equidigital number, since it uses as much as digits as its factorization.

1313151143903 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14580, while the sum is 35.

The spelling of 1313151143903 in words is "one trillion, three hundred thirteen billion, one hundred fifty-one million, one hundred forty-three thousand, nine hundred three".