Base | Representation |
---|---|
bin | 10011000110111101111… |
… | …010000100111111011111 |
3 | 11122112110202112210010222 |
4 | 103012331322010333133 |
5 | 133003313143101103 |
6 | 2443130414151555 |
7 | 163605052361654 |
oct | 23067572047737 |
9 | 4575422483128 |
10 | 1313151143903 |
11 | 4669a4650265 |
12 | 1925b77b25bb |
13 | 96aa28a88b1 |
14 | 477b2019c2b |
15 | 24258780638 |
hex | 131bde84fdf |
1313151143903 has 2 divisors, whose sum is σ = 1313151143904. Its totient is φ = 1313151143902.
The previous prime is 1313151143893. The next prime is 1313151143917. The reversal of 1313151143903 is 3093411513131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313151143903 - 210 = 1313151142879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313151143503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656575571951 + 656575571952.
It is an arithmetic number, because the mean of its divisors is an integer number (656575571952).
Almost surely, 21313151143903 is an apocalyptic number.
1313151143903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313151143903 is an equidigital number, since it uses as much as digits as its factorization.
1313151143903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 35.
The spelling of 1313151143903 in words is "one trillion, three hundred thirteen billion, one hundred fifty-one million, one hundred forty-three thousand, nine hundred three".
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