1313160240031 has 2 divisors, whose sum is σ = 1313160240032. Its totient is φ = 1313160240030.

The previous prime is 1313160239869. The next prime is 1313160240037. The reversal of 1313160240031 is 1300420613131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1313160240031 - 2¹³ = 1313160231839 is a prime.

It is a super-2 number, since 2×1313160240031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1313160239978 and 1313160240005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313160240037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656580120015 + 656580120016.

It is an arithmetic number, because the mean of its divisors is an integer number (656580120016).

Almost surely, 2^{1313160240031} is an apocalyptic number.

1313160240031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313160240031 is an equidigital number, since it uses as much as digits as its factorization.

1313160240031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1313160240031 its reverse (1300420613131), we get a palindrome (2613580853162).

The spelling of 1313160240031 in words is "one trillion, three hundred thirteen billion, one hundred sixty million, two hundred forty thousand, thirty-one".