1313201131199 has 2 divisors, whose sum is σ = 1313201131200. Its totient is φ = 1313201131198.

The previous prime is 1313201131189. The next prime is 1313201131201. The reversal of 1313201131199 is 9911311023131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1313201131199 - 2²⁸ = 1312932695743 is a prime.

It is a super-2 number, since 2×1313201131199² (a number of 25 digits) contains 22 as substring.

Together with 1313201131201, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313201131159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656600565599 + 656600565600.

It is an arithmetic number, because the mean of its divisors is an integer number (656600565600).

Almost surely, 2^{1313201131199} is an apocalyptic number.

1313201131199 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313201131199 is an equidigital number, since it uses as much as digits as its factorization.

1313201131199 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4374, while the sum is 35.

The spelling of 1313201131199 in words is "one trillion, three hundred thirteen billion, two hundred one million, one hundred thirty-one thousand, one hundred ninety-nine".