Base | Representation |
---|---|
bin | 11101110110111101011001… |
… | …001110010110111011001011 |
3 | 122012222002012002110211100012 |
4 | 131312331121032112323023 |
5 | 114203022102213330324 |
6 | 1143143344202102135 |
7 | 36442365020516222 |
oct | 3566753116267313 |
9 | 565862162424305 |
10 | 131320122011339 |
11 | 3892a607404358 |
12 | 1288a8771aa94b |
13 | 58375854067c1 |
14 | 245dcdbd0dcb9 |
15 | 102ae0ecdb20e |
hex | 776f59396ecb |
131320122011339 has 2 divisors, whose sum is σ = 131320122011340. Its totient is φ = 131320122011338.
The previous prime is 131320122011329. The next prime is 131320122011371. The reversal of 131320122011339 is 933110221023131.
It is an a-pointer prime, because the next prime (131320122011371) can be obtained adding 131320122011339 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131320122011339 is a prime.
It is a super-4 number, since 4×1313201220113394 (a number of 58 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (131320122011329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65660061005669 + 65660061005670.
It is an arithmetic number, because the mean of its divisors is an integer number (65660061005670).
Almost surely, 2131320122011339 is an apocalyptic number.
131320122011339 is a deficient number, since it is larger than the sum of its proper divisors (1).
131320122011339 is an equidigital number, since it uses as much as digits as its factorization.
131320122011339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 32.
The spelling of 131320122011339 in words is "one hundred thirty-one trillion, three hundred twenty billion, one hundred twenty-two million, eleven thousand, three hundred thirty-nine".
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