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131320122011339 is a prime number
BaseRepresentation
bin11101110110111101011001…
…001110010110111011001011
3122012222002012002110211100012
4131312331121032112323023
5114203022102213330324
61143143344202102135
736442365020516222
oct3566753116267313
9565862162424305
10131320122011339
113892a607404358
121288a8771aa94b
1358375854067c1
14245dcdbd0dcb9
15102ae0ecdb20e
hex776f59396ecb

131320122011339 has 2 divisors, whose sum is σ = 131320122011340. Its totient is φ = 131320122011338.

The previous prime is 131320122011329. The next prime is 131320122011371. The reversal of 131320122011339 is 933110221023131.

It is an a-pointer prime, because the next prime (131320122011371) can be obtained adding 131320122011339 to its sum of digits (32).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131320122011339 is a prime.

It is a super-4 number, since 4×1313201220113394 (a number of 58 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (131320122011329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65660061005669 + 65660061005670.

It is an arithmetic number, because the mean of its divisors is an integer number (65660061005670).

Almost surely, 2131320122011339 is an apocalyptic number.

131320122011339 is a deficient number, since it is larger than the sum of its proper divisors (1).

131320122011339 is an equidigital number, since it uses as much as digits as its factorization.

131320122011339 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 32.

The spelling of 131320122011339 in words is "one hundred thirty-one trillion, three hundred twenty billion, one hundred twenty-two million, eleven thousand, three hundred thirty-nine".