Base | Representation |
---|---|
bin | 1011111100011000100011… |
… | …1011011111110101110111 |
3 | 1201111102000111222022221221 |
4 | 2333012020323133311313 |
5 | 3210123330123302132 |
6 | 43532432502451211 |
7 | 2523520336001254 |
oct | 277061073376567 |
9 | 51442014868857 |
10 | 13132012322167 |
11 | 42032896722a2 |
12 | 15810a4433b07 |
13 | 74346072cb0b |
14 | 33584287642b |
15 | 17b8d8ee3e97 |
hex | bf188edfd77 |
13132012322167 has 2 divisors, whose sum is σ = 13132012322168. Its totient is φ = 13132012322166.
The previous prime is 13132012322047. The next prime is 13132012322237. The reversal of 13132012322167 is 76122321023131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13132012322167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13132012322267) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566006161083 + 6566006161084.
It is an arithmetic number, because the mean of its divisors is an integer number (6566006161084).
Almost surely, 213132012322167 is an apocalyptic number.
13132012322167 is a deficient number, since it is larger than the sum of its proper divisors (1).
13132012322167 is an equidigital number, since it uses as much as digits as its factorization.
13132012322167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 34.
Adding to 13132012322167 its reverse (76122321023131), we get a palindrome (89254333345298).
The spelling of 13132012322167 in words is "thirteen trillion, one hundred thirty-two billion, twelve million, three hundred twenty-two thousand, one hundred sixty-seven".
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