Base | Representation |
---|---|
bin | 10011000111000000111… |
… | …011111100011011111101 |
3 | 11122112121022011202022022 |
4 | 103013000323330123331 |
5 | 133003414200333142 |
6 | 2443135431325525 |
7 | 163606240345562 |
oct | 23070073743375 |
9 | 4575538152268 |
10 | 1313201964797 |
11 | 466a203017a8 |
12 | 1926108208a5 |
13 | 96ab0290828 |
14 | 477b8a88869 |
15 | 2425ce6d6d2 |
hex | 131c0efc6fd |
1313201964797 has 2 divisors, whose sum is σ = 1313201964798. Its totient is φ = 1313201964796.
The previous prime is 1313201964761. The next prime is 1313201964847. The reversal of 1313201964797 is 7974691023131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 946007171641 + 367194793156 = 972629^2 + 605966^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313201964797 - 224 = 1313185187581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313201964707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656600982398 + 656600982399.
It is an arithmetic number, because the mean of its divisors is an integer number (656600982399).
Almost surely, 21313201964797 is an apocalyptic number.
It is an amenable number.
1313201964797 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313201964797 is an equidigital number, since it uses as much as digits as its factorization.
1313201964797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1714608, while the sum is 53.
The spelling of 1313201964797 in words is "one trillion, three hundred thirteen billion, two hundred one million, nine hundred sixty-four thousand, seven hundred ninety-seven".
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