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13132058477 is a prime number
BaseRepresentation
bin11000011101011101…
…10100111101101101
31020220012021200122012
430032232310331231
5203343301332402
610011025331005
7643265440526
oct141656647555
936805250565
1013132058477
11562978299a
122665a96a65
13131385b405
148c810384d
1551cd3a452
hex30ebb4f6d

13132058477 has 2 divisors, whose sum is σ = 13132058478. Its totient is φ = 13132058476.

The previous prime is 13132058461. The next prime is 13132058479. The reversal of 13132058477 is 77485023131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9812685481 + 3319372996 = 99059^2 + 57614^2 .

It is an emirp because it is prime and its reverse (77485023131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13132058477 - 24 = 13132058461 is a prime.

Together with 13132058479, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13132058479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566029238 + 6566029239.

It is an arithmetic number, because the mean of its divisors is an integer number (6566029239).

Almost surely, 213132058477 is an apocalyptic number.

It is an amenable number.

13132058477 is a deficient number, since it is larger than the sum of its proper divisors (1).

13132058477 is an equidigital number, since it uses as much as digits as its factorization.

13132058477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 141120, while the sum is 41.

The spelling of 13132058477 in words is "thirteen billion, one hundred thirty-two million, fifty-eight thousand, four hundred seventy-seven".