1313211132031 has 2 divisors, whose sum is σ = 1313211132032. Its totient is φ = 1313211132030.

The previous prime is 1313211132029. The next prime is 1313211132043. The reversal of 1313211132031 is 1302311123131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1313211132031 - 2¹ = 1313211132029 is a prime.

It is a super-2 number, since 2×1313211132031² (a number of 25 digits) contains 22 as substring.

Together with 1313211132029, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1313211131993 and 1313211132011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313211132061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656605566015 + 656605566016.

It is an arithmetic number, because the mean of its divisors is an integer number (656605566016).

Almost surely, 2^{1313211132031} is an apocalyptic number.

1313211132031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313211132031 is an equidigital number, since it uses as much as digits as its factorization.

1313211132031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1313211132031 its reverse (1302311123131), we get a palindrome (2615522255162).

The spelling of 1313211132031 in words is "one trillion, three hundred thirteen billion, two hundred eleven million, one hundred thirty-two thousand, thirty-one".