Base | Representation |
---|---|
bin | 10011000111000001100… |
… | …110000101100001100111 |
3 | 11122112122001222000022121 |
4 | 103013001212011201213 |
5 | 133003430012341241 |
6 | 2443140504210411 |
7 | 163606433266432 |
oct | 23070146054147 |
9 | 4575561860277 |
10 | 1313213012071 |
11 | 466a26567784 |
12 | 192614469a07 |
13 | 96ab265ac8c |
14 | 477ba322819 |
15 | 2425de01ad1 |
hex | 131c1985867 |
1313213012071 has 2 divisors, whose sum is σ = 1313213012072. Its totient is φ = 1313213012070.
The previous prime is 1313213012051. The next prime is 1313213012141. The reversal of 1313213012071 is 1702103123131.
It is a weak prime.
It is an emirp because it is prime and its reverse (1702103123131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313213012071 - 215 = 1313212979303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313213012051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656606506035 + 656606506036.
It is an arithmetic number, because the mean of its divisors is an integer number (656606506036).
Almost surely, 21313213012071 is an apocalyptic number.
1313213012071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313213012071 is an equidigital number, since it uses as much as digits as its factorization.
1313213012071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 25.
The spelling of 1313213012071 in words is "one trillion, three hundred thirteen billion, two hundred thirteen million, twelve thousand, seventy-one".
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