Base | Representation |
---|---|
bin | 1011111100011001010101… |
… | …1000000010011000001101 |
3 | 1201111102120001212212210202 |
4 | 2333012111120002120031 |
5 | 3210124242102132003 |
6 | 43532505322143245 |
7 | 2523525452562221 |
oct | 277062530023015 |
9 | 51442501785722 |
10 | 13132221130253 |
11 | 4203386520965 |
12 | 1581142351b25 |
13 | 743494a7c2b4 |
14 | 3358624ac781 |
15 | 17b8ec4dd088 |
hex | bf19560260d |
13132221130253 has 2 divisors, whose sum is σ = 13132221130254. Its totient is φ = 13132221130252.
The previous prime is 13132221130177. The next prime is 13132221130261. The reversal of 13132221130253 is 35203112223131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11150877739849 + 1981343390404 = 3339293^2 + 1407602^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13132221130253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13132226130253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566110565126 + 6566110565127.
It is an arithmetic number, because the mean of its divisors is an integer number (6566110565127).
Almost surely, 213132221130253 is an apocalyptic number.
It is an amenable number.
13132221130253 is a deficient number, since it is larger than the sum of its proper divisors (1).
13132221130253 is an equidigital number, since it uses as much as digits as its factorization.
13132221130253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 13132221130253 its reverse (35203112223131), we get a palindrome (48335333353384).
The spelling of 13132221130253 in words is "thirteen trillion, one hundred thirty-two billion, two hundred twenty-one million, one hundred thirty thousand, two hundred fifty-three".
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